4z^(1/3)(2z^(2/3)-3z^6)

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Solution for 4z^(1/3)(2z^(2/3)-3z^6) equation: 


z in (-oo:+oo)

4*z^(1/3)*(2*z^(2/3)-(3*z^6)) = 0

4*z^(1/3)*(2*z^(2/3)-3*z^6) = 0

2*z^(2/3)-3*z^6 = 0

z^(2/3)*(2-3*z^(16/3)) = 0

-3*z^(16/3) = -2 // : -3

z^(16/3) = 2/3

z^(16/3) = 2/3 // ^ 3

z^16 = 8/27 // ^ 1/16

abs(z) = (8/27)^(1/16)

z = (8/27)^(1/16) or z = -(8/27)^(1/16)

z^(2/3)*(z-(8/27)^(1/16))*(z+(8/27)^(1/16)) = 0

4*z^(1/3)*z^(2/3)*(z-(8/27)^(1/16))*(z+(8/27)^(1/16)) = 0

( 4*z^(1/3) )

4*z^(1/3) = 0 // : 4

z^(1/3) = 0

z = 0

( z+(8/27)^(1/16) )

z+(8/27)^(1/16) = 0 // - (8/27)^(1/16)

z = -(8/27)^(1/16)

( z-(8/27)^(1/16) )

z-(8/27)^(1/16) = 0 // + (8/27)^(1/16)

z = (8/27)^(1/16)

( z^(2/3) )

1*z^(2/3) = 0 // : 1

z^(2/3) = 0

z = 0

z in { 0, -(8/27)^(1/16), (8/27)^(1/16), 0 }

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